Find the intersection between three cycles (or more) with Shapely

Question

In Shapely's tutorial there is a nice example (illustrated bellow) on how to find the intersection between exactly two points:

a = Point(1, 1).buffer(1.5)
b = Point(2, 1).buffer(1.5)
a.intersection(b)
a.union(b)

What it doesn't say though is how to find the intersection between more than three points at the same time. Any ideas?

Answer 1

Sure it does, see shapely.ops.cascaded_union. There is no equivalent for intersection, but you just need to accumulate a result:

result = a.intersection(b)
result = result.intersection(c)

More tricks here.