There are many ways to put the pieces of the puzzle together. Finding the tool for the job is 1/2 the battle. In this case strtol will covert base 2 to decimal. The key is to recognize, there is no reason to do character input and you can simplify your code using line-oriented input which will provide your data in a format ready for conversion.
Below are the pieces of the puzzle. They are left somewhat out of order so that you can work to rearrange them to produce a final output file with both the string and the decimal value contained within it. You will probably want to open your output file before you read the text file so that both file steams are available during your read loop.
Take a look and let me know if you have any questions. Note: this is just one of many, many ways to approach this problem:
#include <stdio.h>
#include <stdlib.h>
#define MAXN 100
int main () {
char file_input[25] = { 0 }; /* always initialize all variables */
char file_output[25] = { 0 };
FILE *fi = NULL;
FILE *fo = NULL;
int integers[MAXN] = { 0 };
int i = 0;
int num = 0;
printf ("\n Please enter the input filename: ");
while (scanf ("%[^\n]%*c", file_input) != 1)
fprintf (stderr, "error: read failed for 'file_input', try again\n filename: ");
fi = fopen (file_input, "r"); /* open input file and validate */
if (!fi) {
perror ("Error while opening the file.\n");
exit (EXIT_FAILURE);
}
printf ("\n The contents of file '%s' are :\n\n", file_input);
char *line = NULL; /* NULL forces getline to allocate */
size_t n = 0; /* max chars to read (0 - no limit */
ssize_t nchr = 0; /* number of chars actually read */
while ((nchr = getline (&line, &n, fi)) != -1) {
if (line[nchr - 1] == '\n')
line[--nchr] = 0; /* strip newline from end of line */
integers[i] = strtol (line, NULL, 2); /* convert to decimal */
printf (" %s -> %d\n", line, integers[i]);
if (i == MAXN - 1) { /* check MAXN limit not exceeded */
fprintf (stderr, "error: input lines exceed %d\n", MAXN);
exit (EXIT_FAILURE);
}
i++;
}
if (line) free(line); /* free memory allocated by getline */
if (fi) fclose (fi); /* close file stream when done */
num = i; /* save number of elements in array */
printf ("\n Conversion complete, output filename: ");
while (scanf ("%[^\n]%*c", file_output) != 1)
fprintf (stderr, "error: read failed for 'file_output', try again\n filename: ");
fo = fopen (file_output, "w+"); /* open output file & validate */
if (!fo) {
perror ("Error while opening the file.\n");
exit (EXIT_FAILURE);
}
for (i = 0; i < num; i++) /* write integers to output file */
fprintf (fo, " %d\n", integers[i]);
if (fo) fclose (fo);
return 0;
}
Use/output:
$ ./bin/arrayhelp
Please enter the input filename: dat/binin.txt
The contents of file 'dat/binin.txt' are :
01000101 -> 69
11010110 -> 214
11101110 -> 238
Conversion complete, output filename: dat/binout.txt
$ cat dat/binout.txt
69
214
238
Reading Character-by-character
While this isn't the easiest way to handle reading the file, there is nothing wrong with it. However, you have logic problems. Specifically, you read (and assign as integer) numi = ch; and then assign numo = numi + 8; to write to your output file. This results in adding 8 to the ASCII value of '0' (48) or '1' (49). If you add 8 to that, well, you can do the math. When you read from a file as text, you are reading the ASCII value, NOT the numeric value 1 or 0.
In order to accomplish what you appear to be attempting, you must save all characters in a line to a buffer (a string, a character array, I don't care what you call it). That is the only way, (short of doing a character-by-character conversion to a numeric 1 or 0 and then preforming the binary addition), you have to convert the string of '0's and '1's to a decimal value.
Here is an example using the character-by-character read from fi. Read though it and understand why it needs to be done this way. If you have questions, drop another comment.
#include <stdio.h>
#include <stdlib.h>
#define MAXN 100
int main () {
int ch = 0;
FILE *fi = NULL;
FILE *fo = NULL;
// int numo = 0;
// int numi = 0;
// int nump = 0;
char buffer[MAXN] = { 0 }; /* buffer to hold each line */
int idx = 0; /* index for buffer */
fo = fopen ("OutputFile.txt", "w+"); /* open output file & validate */
if (!fo) {
perror ("Error while opening the file.\n");
exit (EXIT_FAILURE);
}
fi = fopen ("InputFile.txt", "r"); /* open input file & validate */
if (!fi) {
perror ("Error while opening the file.\n");
exit (EXIT_FAILURE);
}
printf ("\n The contents of %s file are :\n\n", "InputFile.txt");
fprintf (fo, " binary decimal\n"); /* header for output file */
while (1) /* loop and test for both '\n' and EOF (-1) to parse file */
{
// printf ("%c", ch); /* we will store each ch in line in buffer */
if ((ch = fgetc (fi)) == '\n' || ch == EOF)
{
if (ch == EOF && idx == 0) /* if EOF (-1) & buffer empty exit loop */
break;
buffer[idx] = 0; /* null-terminate buffer (same as '\0' ) */
idx = 0; /* reset index for next line & continue */
/* write original value & conversion to fo */
fprintf (fo, " %s => %ld\n", buffer, strtol (buffer, NULL, 2));
/* write fi contents to stdout (indented) */
printf (" %s\n", buffer);
}
else
{
buffer[idx++] = ch; /* assign ch to buffer, then increment idx */
}
/* This makes no sense. You are reading a character '0' or '1' from fi,
the unsigned integer value is either the ASCII value '0', which is
decimal 48 (or hex 0x30), or the ASCII value '1', decimal 49/0x31.
If you add 8 and write to 'fo' with '%d' you will get a 16-digit
string of a combination of '56' & '57', e.g. 56575756....
numi = ch;
numo = numi + 8;
*/
}
if (fi) /* close both input and output file streams */
fclose (fi);
if (fo)
fclose (fo);
return 0;
}
output to stdout:
$ ./bin/arrayhelp2
The contents of InputFile.txt file are :
01000101
11010110
11101110
OutputFile.txt:
$ cat OutputFile.txt
binary decimal
01000101 => 69
11010110 => 214
11101110 => 238
