So, I have a very large number that I'm working out in python, but when I try to print it I get something like this:
3.101541146879488e+80
How do I print all the digits of my lovely number?
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8how is the data created? Have a look at the [decimal madule](https://docs.python.org/2/library/decimal.html) – Fredrik Pihl Dec 05 '14 at 22:35
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Have you read about [string formatting in Python](https://docs.python.org/2/library/stdtypes.html#string-formatting)? How do you know there are more digits? – Air Dec 05 '14 at 22:35
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is `long(x)` okay for this? – TehTris Dec 05 '14 at 22:37
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1If this is a real number and not a Decimal, only about 15 or 16 of those digits are going to be accurate anyway. – Mark Ransom Dec 05 '14 at 23:03
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@C.B. Python has had unlimited size longs for a while now. – Mark Ransom Dec 05 '14 at 23:04
1 Answers
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both int and long work for this
>>> a
3.101541146879488e+80
>>> int(a)
310154114687948792274813492416458874069290879741385354066259033875756607541870592L
>>> long(a)
310154114687948792274813492416458874069290879741385354066259033875756607541870592L
>>> print (int(a))
310154114687948792274813492416458874069290879741385354066259033875756607541870592
>>> print (long(a))
310154114687948792274813492416458874069290879741385354066259033875756607541870592
Bhargav Rao
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4Note that if `a` is a float most of those digits are simply an artefact of the way it is stored at IEEE-754 double precision – xnx Dec 06 '14 at 00:14
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