How to cout array values in c++

Asked Dec 01 '14 at 02:39

Active Dec 01 '14 at 02:39

Viewed 47 times

am trying to cout all values in an array like this

int collect[8],c;
for(c = 0; c <= 4; c++)
{
    cout << "Enter First Number : ";
    cin >> collect[c];
}
cout << collect[0, 1, 2, 3, 4] << endl;

but it displays the last value. Please leave some note to make me understand why its not working

asked Dec 01 '14 at 02:39

Ghostff

1,407
3
18
30

Array indexing doesn't work with multiple indexes. It's not a syntax error because you're using the 'comma operator', which evaluates to the last element. You need another for loop. – sje397 Dec 01 '14 at 02:42
You got it right with `cin`. You need to do same with `cout` i.e. `cout << collect[c]` in a `for` loop. – rockoder Dec 01 '14 at 02:43
1

Congratulations! You've met the `comma operator` seeing it working in full glory :-P ... – πάντα ῥεῖ Dec 01 '14 at 02:45
@πάντα ῥεῖ i saw the other question that looks just like mine. i dont understand it because am a noob to c++ – Ghostff Dec 01 '14 at 02:48
@ChrysUgwu Effectively it means `collect[0, 1, 2, 3, 4]` is actually equivalent to `collect[4]`. – πάντα ῥεῖ Dec 01 '14 at 02:49
okay cant i cout all of them with loop? – Ghostff Dec 01 '14 at 02:51
@ChrysUgwu With a loop of course you can: `for(int i = 0; i < 5; ++i) { cout << collect[i]; } cout << std::endl;` – πάντα ῥεῖ Dec 01 '14 at 02:54
sorry what if without a loop – Ghostff Dec 01 '14 at 02:55
@ChrysUgwu _"sorry what if without a loop"_ There's no _without a loop_, unless you provide an appropriate overload for `std::ostream& operator<<(std::ostream&, const int[8])` and have the loop within the implementation of that overloaded function. – πάντα ῥεῖ Dec 01 '14 at 02:56
Let us [continue this discussion in chat](http://chat.stackoverflow.com/rooms/65922/discussion-between-chrys-ugwu-and--). – Ghostff Dec 01 '14 at 02:58
@ChrysUgwu _"Let us continue this discussion in chat."_ Nope! I've said everything relevant. – πάντα ῥεῖ Dec 01 '14 at 02:59

How to cout array values in c++

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