how to compare between two Tuples?

Question

Write a function commonElements(t1, t2) that takes in 2 tuples as arguments and returns a sorted tuple containing elements that are found in both tuples.

Examples

>>> commonElements((1, 2, 3), (2, 5, 1))
(1, 2)
>>> commonElements((1, 2, 3, 'p', 'n'), (2, 5 ,1, 'p'))
(1, 2, 'p')
>>> commonElements((1, 3, 'p', 'n'), ('a', 2 , 5, 1, 'p'))
(1, 'p')

i want to compare between two tuples

 def commonElements(t1,t2):
     if t1 in t2:
        return t1

possible duplicate of [Tuple Comparison](http://stackoverflow.com/questions/4405122/tuple-comparison) — , Nov 23 '14 at 11:49
i want to be professional in python but i don`t know what shall i do :) i am a beginner i want some helps and advices :) — Ramy George, Nov 23 '14 at 11:55
Grab a book and stop posting your homework in stack overflow! — Javier Castellanos, Nov 23 '14 at 12:35

Padraic Cunningham · Accepted Answer · 2014-11-23T12:10:59.763

1

You would need to check if each element in t1 is in t2, your code just returns t1 when you find the first common element or None if there are no common elements:

def commonElements(t1,t2):
    temp = []  # store  common elements
    st2  = set(t2)
    for ele in t1: # loop over each element in t1
        if ele in st2: # if it is in t2 add it to or temp list, set lookups are O(1)
            temp.append(ele)
    return tuple(sorted(temp)) # sort temp and convert to a tuple

In [4]: commonElements((1, 2, 3), (2, 5, 1))
Out[4]: (1, 2)

In [5]: commonElements((1, 2, 3, 'p', 'n'), (2, 5 ,1, 'p'))
Out[5]: (1, 2, 'p')

In [6]: commonElements((1, 3, 'p', 'n'), ('a', 2 , 5, 1, 'p'))
Out[6]: (1, 'p')

You can also use sets or a generator expression:

def  commonElements(t1,t2):
     # find the intersection/common elements
    return tuple(sorted(set(t1).intersection(t2)))

def  commonElements(t1,t2):
    return tuple(sorted(ele for ele in t1 if ele in t2))

edited Nov 23 '14 at 12:10

answered Nov 23 '14 at 11:59

Padraic Cunningham

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@vaultah, where does it say python 3? – Padraic Cunningham Nov 23 '14 at 12:01
@vaultah, well presuming the task is to sort the output i imagine the teacher is not going to give a beginner that problem – Padraic Cunningham Nov 23 '14 at 12:02
1

i want some advices to be professional in python @Padraic Cunningham – Ramy George Nov 23 '14 at 12:06
@RamyGeorge, sets are most efficient if dealing with large amounts of data. – Padraic Cunningham Nov 23 '14 at 12:14
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@PadraicCunningham i want to be professional coder what shall i do ? – Ramy George Nov 23 '14 at 12:15
@RamyGeorge, the python practice book is a really useful resource http://anandology.com/python-practice-book/getting-started.html – Padraic Cunningham Nov 23 '14 at 12:17
@PadraicCunningham Thank you very much :) i want to ask another question can we make computer do 2+2=7 ? – Ramy George Nov 23 '14 at 12:20
@RamyGeorge, not without hardcoding it some way – Padraic Cunningham Nov 23 '14 at 12:21
1

what do you mean by hardcoding ? can you explain ? – Ramy George Nov 23 '14 at 12:27
@RamyGeorge, without changing your python implementation source you would have to use run the code through some function – Padraic Cunningham Nov 23 '14 at 12:41

Alexander · Answer 2 · 2014-12-11T21:56:44.647

1

You could use operator based intersection of sets .

def commonElements(one, two):
    return tuple(sorted(set(one) & set(two)))

commonElements((1,2,3), (2,3,4))
# (2, 3)

edited Dec 11 '14 at 21:56

answered Nov 23 '14 at 11:59

Alexander

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how to compare between two Tuples?

2 Answers2