Chai-as-promised, Promised array must be loosely-equal

Question

Is there a way to assert that a promise array equals your gold standard, minus ordering? Deep equal fails because the ordering isn't guaranteed - the array is being built asynchronously.

As far as I can tell, CaP doesn't include a ".should.eventually.include.all([])" or anything like that. I don't think I'd be able to check every entry, because then where would the notify(done) be chained?

juunas · Answer 1 · 2015-02-24T05:24:38.833

0

The Chai Things plugin might help you.

You could for example do something like:

.should.eventually.include.something.that.equals(promiseA);
.should.eventually.include.something.that.equals(promiseB);
.should.eventually.include.something.that.equals(promiseC);

edited Feb 24 '15 at 05:24

answered Feb 24 '15 at 03:15

juunas

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score 0 · Answer 2 · answered Jan 05 '16 at 22:13

If I understand your question correctly you should be able to do it like this:

        Promise.all(arrayOfPromises).then(function (results) {
            //so check your results here
            for (var i = 0; i < results.length; i++) {
                results[i].should.have....
            }

           //and the notify(done) is chained after this
        }).should.eventually.notify(done);

I hope that helps.

Chai-as-promised, Promised array must be loosely-equal

2 Answers2