error in using switch case

Question

in the following code:

    switch(a)
    {

    case '+' :
        result=num1+num2;
    break;

    case '-' :
        result=num1-num2;
    break;

    case '*' :
        result=num1*num2;
    break;

    case '/' :
        result=num1/num2;
    break;

    case '^' :
        result=pow(num1,num2);
    break;

    default :
       cout << "Invalid operator" << endl;
    }

is the char pointer, and the error is: error: switch quantity not an integer...

I don't understand, is a a char or char pointer. If it's a char pointer, that would explain why you are getting an error — James H, Nov 13 '14 at 18:43

score 3 · Accepted Answer · answered Nov 13 '14 at 18:43

3

If a is a pointer, you cannot use it in the switch: you need to dereference it first - either like this

switch(*a)

or like this

switch(a[0])

answered Nov 13 '14 at 18:43

Sergey Kalinichenko

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Yep, this. I would guess if a is a char *, then that would explain the error. – James H Nov 13 '14 at 18:44
thaks for that, it's working correctly – Shiraz Hussain Malkani Nov 15 '14 at 04:45

error in using switch case

1 Answers1