find and replace percent symbol within string with back slash in ruby?

Question

I tried this :

irb(main):125:0> a = "ab%c"
=> "ab%c"
irb(main):126:0> a.gsub("%", '\\')
=> "ab\\c"
irb(main):127:0>

whereas expected output is:

ab\c

it did not work.

Thanks in advance.

Update: ruby version

ruby -v
ruby 1.8.7 (2011-06-30 patchlevel 352) [x86_64-linux]

It did work. Why do you claim it didn't? `puts a.gsub('%', '\\') # => ab\c`. — Marek Lipka, Nov 12 '14 at 10:52
It didn't work for me in ruby -v ruby 1.8.7 (2011-06-30 patchlevel 352) [x86_64-linux] — Vikash Singh, Nov 12 '14 at 11:21
sorry, but it isen't. expected output is ab\c whereas i am getting ab\\c. — Vikash Singh, Nov 12 '14 at 11:29
Again: Did you bother reading my comment and shivam's answer? — Marek Lipka, Nov 12 '14 at 11:30

score 2 · Accepted Answer · answered Nov 12 '14 at 10:54

2

a = "ab%c"
a.gsub!("%", '\\')  
#=> "ab\\c"
puts a
# ab\c

in "ab\\c" backslash \ is being escaped using character \. you can verify this with puts

answered Nov 12 '14 at 10:54

shivam

1 Answers1