Conversion form int to long

Question

I have created a class called Employee and I have an ArrayList for storing all the contact numbers of the employee. I have defined a method called addcontact() to add numbers to the list. If I use an int then it says that the number is out of range, so I changed it to long, but still I get the same error.

I am using Externalizable to serialize and deserialize the Employee details.

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use `1231241241212121l` :P – TheLostMind Oct 29 '14 at 05:53 — TheLostMind, Oct 29 '14 at 05:53

score 3 · Accepted Answer · answered Oct 29 '14 at 05:53

3

You should add L at the end of that number (eg. 1234567890123L). Otherwise, it's considered an int constant, and therefore out of range.

answered Oct 29 '14 at 05:53

Eran

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score 2 · Answer 2 · answered Oct 29 '14 at 05:54

2

Values of type long should have an L at the end: 9929929939L.

answered Oct 29 '14 at 05:54

RealSkeptic

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score 1 · Answer 3 · answered Oct 29 '14 at 06:06

1

Int
Minimum value is - 2,147,483,648.(-2^31)
Maximum value is 2,147,483,647(inclusive).(2^31 -1)

Long
Minimum value is -9,223,372,036,854,775,808.(-2^63)
Maximum value is 9,223,372,036,854,775,807 (inclusive). (2^63 -1)

answered Oct 29 '14 at 06:06

SonalPM

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Conversion form int to long

3 Answers3