Convert from string to UInt32 - C#

Question

I read UInt32 value as a string from XML file. And then I want to convert it to UInt32.

UInt32 res = Convert.ToUInt32("0x00B73004", 16);

But after converting the resulting value is: 12005380

Why it is so?

Answer 1

It's working just as intended. 0xB73004 (with any number of leading zeroes) is 12005380 in decimal notation.

>>> hex(12005380)
'0xb73004'

Answer 2

As other answers suggest, the hexidecimal number B73004 equals the decimal number 12005380.

What you might forget is an UInt32 cannot hold any formatting. UInt32 is just a combination of 32 bits which represents a number; a value. How that number is displayed is entirely up to you. You can display it as an hexidecimal, binairy or decimal number. Example:

Console.WriteLine("{0} = {0:X}", res);

You can even tell Visual Studio to display the values in hexidecimal format with right-click on the Watch window and select 'Hexidecimal Display'.

This behavior is the same with float point number: It does not contain any information if it should be formatted with a dot or comma. That depends on the (current) culture. Also for the DateTime: It contains a date and time, without any formatting. The programmer can define how that date and time should be displayed (For example like: dd-MM-yyyy or yyyy-MM-dd, etc.)

Answer 3

0x00B73004 is just hexadecimal notation of 12005380. Prefix "0x" is the most common notation to represents hexadecimal constants.

Since you asking why here a math side;

00B73004₁₆ = 0 * 16⁷ + 0 * 16⁶ + B * 16⁵ + 7 * 16⁴ + 3 * 16³ + 0 * 16² + 0 * 16¹ + 4 * 16⁰

= 0 + 0 + 11 * 16⁵ + 7 * 16⁴ + 3 * 16³ + 0 * 16² + 0 * 16¹ + 4 * 16⁰

= 0 + 0 + 11534336 + 458752 + 12288 + 0 + 0 + 4

= 12005380

By the way B_hex = 11_dec

You can save this hexadecimal notation in a numeric value like;

uint i = 0x00B73004;

Nothing wrong with that. You can see it's base 10 value on debugger.