Android generate small color difference RGB

Question

I want to generate/randomize a color and then I want second one that is close to the generated one. This is how I generate the colors ftm:

Paint colors = new Paint();

int red = ran.nextInt(256-100)+100;
int green = ran.nextInt(256-100)+100;
int blue = ran.nextInt(256-100)+100;

colors.setARGB(255, red, green, blue);

and later the 2nd color I generate like this:

switch (ran.nextInt(3)) {
        case 0:
            red = red - (40 - level);
            break;
        case 1:
            green = green - (40 - level);
            break;
        default:
            blue = blue - (40-level);
            break;
        }

The problem is that it works in some cases and sometimes it can give me a 2nd color that is off by miles. Is there another, better and easier way to generate these colors?

br

there's other color spaces, like hsv, which are better suited to manipulation for producing "similar" colors. — Marc B, Oct 22 '14 at 19:11
@MarcB +1 ...and tinyColor.js easily converts between rgb and hsl: http://bgrins.github.io/TinyColor/docs/tinycolor.html — markE, Oct 22 '14 at 19:50

Jorgesys · Answer 1 · 2014-10-22T19:34:07.483

You need to create a real random number between 0 and 3:

 Random ran = new Random();
 int max = 3;
 int min = 0;
 int randomNum = ran.nextInt((max - min) + 1) + min;

switch (randomNum ) {
        case 0:
            red = red - (40 - level);
            break;
        case 1:
            green = green - (40 - level);
            break;
        default:
            blue = blue - (40-level);
            break;
        }

score 0 · Answer 2 · answered Oct 22 '14 at 21:26

0

You could use java.awt.Color.brighter() and Color.darker().

answered Oct 22 '14 at 21:26

Minesweep

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Android generate small color difference RGB

2 Answers2