subscripted value is neither array nor pointer nor vector with argv

Question

I have this code.c in ubuntu in terminal but when I compile it with gcc this error appeared

cod2.c: In function ‘main’:
cod2.c:9:11: error: subscripted value is neither array nor pointer nor vector

why is that?

int  main(int argc , char ** argv){
    mkdir(argc[1] , 00755);
    return 0;
}

Paul R · Accepted Answer · 2014-10-22T08:23:20.030

0

You got confused between argc (an int representing the number of arguments) and argv (an array of strings containing the command line arguments). Change:

mkdir(argc[1], 00755);

to:

mkdir(argv[1], 0755);
      ^^^^^^^

(Note that I also removed a redundant 0 prefix from 00755 to make it 0755 - you only need a single 0 prefix to signify octal base.)

For a real program you should also check that an argument has been provided, otherwise you will crash when the user does not supply an argument:

if (argc > 1)
{
    mkdir(argv[1], 0755);
}

edited Oct 22 '14 at 08:23

answered Oct 22 '14 at 08:10

Paul R

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nothing has changed! yes argc was false but 00755 was true :) – patric Oct 22 '14 at 08:13
Did you change `argc` to `argv`, save and re-compile ? – Paul R Oct 22 '14 at 08:15
yes you are right :) argv is correct but 0 doesn't have problem – patric Oct 22 '14 at 08:19
You mean the change from `00755` to `0755` ? I just fixed that because the extra `0` is redundant - you only need one `0` prefix to signify octal base. – Paul R Oct 22 '14 at 08:20

score 0 · Answer 2 · answered Oct 22 '14 at 08:11

0

 mkdir(argv[1] , 00755);//try argv instead of argc

Your command line arguments are stored in argv only, not in argc. argc contains no of arguments in command lines. So try with argv

answered Oct 22 '14 at 08:11

Anbu.Sankar

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subscripted value is neither array nor pointer nor vector with argv

2 Answers2