In Java, how do you print out an anwer in a different literal?

Question

I know that you add an L to a value if it exceeds the scope of an integer but you still have to print it as such. I understand the concept of doing it when you're just printing out a plain number.

What about when you're using a defined variable instad?

Say I have something like.

double a = 2.5;
System.out.println(a);

I want "a" to be printed out as a integer.

Thanks for any answers in advance :)

If you were to print it out as an integer, it would be rounded to the nearest whole number. — Santiago Benoit, Oct 18 '14 at 16:39

score 1 · Answer 1 · answered Oct 18 '14 at 16:38

1

You can use Math.round for instance.

System.out.println(Math.round(a));

or you can format it as an integer as follows:

System.out.printf("%.0f%n", a);

answered Oct 18 '14 at 16:38

aioobe

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score 0 · Answer 2 · answered Oct 18 '14 at 16:39

0

cast double a to Double and use a.intValue()

Double a = new Double("2.5");
System.out.println(a.intValue());

answered Oct 18 '14 at 16:39

Jean-François Savard

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Hmm all of these methods seem to work, the book I was using didn't mention any of them for some reason. I guess it expected me to ask this on stack overflow. Cheers guys. – itsmetheperson Oct 18 '14 at 16:47

score 0 · Answer 3 · answered Oct 18 '14 at 16:50

You could use a NumberFormat. There are predefined formats available which you could use for your particular use-case.

NumberFormat format = NumberFormat.getIntegerInstance();
double a = 2.5;
System.out.println( format.format( a ) );

But it also allows to create one for more difficult output, like with a specified number of decimals. That would be much harder using Math.round or the other suggestions made here.

In Java, how do you print out an anwer in a different literal?

3 Answers3