how to exit python execfile() with out exiting whole script

Question

I have a code which runs mutile python codes such as below:

execfile("1.py")
execfile("2.py")
execfile("3.py")

however occasionally one of the above codes as an error, i put exit('error') in the code to cancell if there is an error. However i want the rest of the code to run and exit('error') exits the whole code, not just the execfile. How do i get the execfile to stop but the others to keep running?

The part of 1.py with exit() is:

try :
    Ntot=10000
    x,y,s=myMCMC2D(Ntot,0.78,0.63,1,1)
except :
    exit('error')

This reminds me of the old joke. "doctor, it hurts when I do this." "Well, then, stop doing that". If you don't want your programs to exit when they encounter an error, then don't call `exit` in the except clause in your programs. — Kevin, Oct 15 '14 at 12:27

score 3 · Accepted Answer · answered Oct 15 '14 at 12:22

3

try:
    execfile('1.py')
except SystemExit:
    print "1.py exited"

Exit is an exception which can be caught.

answered Oct 15 '14 at 12:22

Łukasz Rogalski

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Actually `exit()` is function that raises a `SystemExit` exception when called. – martineau Oct 15 '14 at 13:24

how to exit python execfile() with out exiting whole script

1 Answers1