rspec yield block, but call original

Question

So I have the following:

foo.each do |f|
  f.begin
    do_stuff
    do_more_stuff
  end
end

And I mock the f object with an and_yield() call. I want to be able to test the begin method by passing it the original block { do_stuff do_more_stuff }, not a mock implementation.... I cant just let the begin method be called on the mock without at least stubbing it, so what do I do?

score 19 · Accepted Answer · answered Oct 14 '14 at 20:59

19

Again, an undocumented feature that i found:

allow(thing).to receive(:foo) do |_, &block|
  block.call
end

le sigh....

answered Oct 14 '14 at 20:59

Nicholas Terry

1,812
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3

Not undocumented: https://www.relishapp.com/rspec/rspec-mocks/v/3-1/docs/configuring-responses/block-implementation – zetetic Oct 14 '14 at 21:19
Awesomesauce! I guess I am just blind – Nicholas Terry Oct 16 '14 at 20:31

score 3 · Answer 2 · edited Nov 15 '21 at 13:49

3

The following worked for me:

original = thing.method(:foo)
expect(thing).to receive(:foo) do |_params|
  # check params
  expect(params).to include(something)

  # then
  original.call(params)
end

edited Nov 15 '21 at 13:49

Tomerikoo

18,379
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answered Nov 15 '21 at 13:41

Nathan Gouy

1,072
9
19

rspec yield block, but call original

2 Answers2