2

I'm trying to cut an image into 9 pieces in Swift. I'm getting this error:

'CGFloat' is not convertible to 'Double'

I get this error when I put i or j in the two variables.

Below is part of the code used for cutting the image.

for i in 1...3
    {
        for j in 1...3
        {
            var intWidth = ( i * (sizeOfImage.width/3.0))
            var fltHeight = ( j * (sizeOfImage.height/3.0))
        var portion = CGRectMake(intWidth,fltHeight, sizeOfImage.width/3.0, sizeOfImage.height/3.0);
            .
            .
      "Code goes on"

What is the problem?

Cœur
  • 37,241
  • 25
  • 195
  • 267
Riyazul Aboobucker
  • 496
  • 8
  • 20

2 Answers2

3

In swift there is no implicit conversion of numeric data types, and you are mixing integers and floats. You have to explicitly convert the indexes to CGFloats:

var intWidth = ( CGFloat(i) * (sizeOfImage.width/3.0))
var fltHeight = ( CGFloat(j) * (sizeOfImage.height/3.0))

As often happening in swift, the error message is misleading - it says:

'CGFloat' is not convertible to 'Double'

whereas I'd expect:

'CGFloat' is not convertible to 'Int'

Antonio
  • 71,651
  • 11
  • 148
  • 165
0

This is a non-starter in Swift 5.5 (automatic conversion). We can pass CGFloat and Double interchangeably to functions that accept either of those types.

Pranav Kasetti
  • 8,770
  • 2
  • 50
  • 71