python isdigit() is True for ④ but int() fails

Asked Oct 09 '14 at 18:22

Active Oct 09 '14 at 18:22

Viewed 96 times

What is the difference between and ④?

>>> u''.isdigit()
True
>>> int(u'')
4
>>> u'④'.isdigit()
True
>> int(u'④')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '④'

Note: above is output on python3. On python last gives this exception:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
UnicodeEncodeError: 'decimal' codec can't encode character u'\u2463' in position 0: invalid decimal Unicode string

asked Oct 09 '14 at 18:22

Taha Jahangir

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just because it looks like a number to us humans, doesn't mean it's actually a number as far as unicode and computers are concerned. – Marc B Oct 09 '14 at 18:25
that's not so simple, why `isdigit()` returns `True` then? – m.wasowski Oct 09 '14 at 18:27
`isdecimal` is False for ④ – Taha Jahangir Oct 09 '14 at 18:31

python isdigit() is True for ④ but int() fails

0 Answers0