I want to convert legacy .vtk
files into binary files, preferably .vtu
files, because I am using an Unstructured Grid.
To do so I adapted the ConvertFile-Example from http://www.vtk.org/Wiki/VTK/Examples/Cxx/IO/ConvertFile
#include <string>
#include <vtkSmartPointer.h>
#include <vtkGenericDataObjectReader.h>
#include <vtkVersion.h>
#include <vtkXMLUnstructuredGridWriter.h>
#include <vtkUnstructuredGrid.h>
int main(int argc, char *argv[])
{
if(argc < 3)
{
std::cerr << "Required arguments: input.vtk output.vtu" << std::endl;
return EXIT_FAILURE;
}
std::string inputFileName = argv[1];
std::string outputFileName = argv[2];
vtkSmartPointer<vtkGenericDataObjectReader> reader = vtkSmartPointer<vtkGenericDataObjectReader>::New();
reader->SetFileName(inputFileName.c_str());
reader->Update();
vtkSmartPointer<vtkXMLUnstructuredGridWriter> writer = vtkSmartPointer<vtkXMLUnstructuredGridWriter>::New();
writer->SetFileName(outputFileName.c_str());
writer->SetInputConnection(reader->GetOutputPort());
writer->Update();
return EXIT_SUCCESS;
}
But when I use this to convert my legacy file, I lose all Cell Data after the first set. In this minimal example of my legacy file Scal_1 is in the .vtu
file but Scal_2 is not.
# vtk DataFile Version 3.1
Lattice Boltzmann data
ASCII
DATASET UNSTRUCTURED_GRID
POINTS 9 INT
0 0 0 1 0 0 2 0 0
0 1 0 1 1 0 2 1 0
0 2 0 1 2 0 2 2 0
CELLS 4 20
4 0 1 3 4
4 1 2 4 5
4 3 4 6 7
4 4 5 7 8
CELL_TYPES 4
8 8 8 8
CELL_DATA 4
SCALARS Scal_1 DOUBLE
LOOKUP_TABLE default
1 2 1 0
SCALARS Scal_2 DOUBLE
LOOKUP_TABLE default
1 3 2 1
I am still new to vtk
. Should I use another reader or writer? Or is something completely wrong?