Why does "double z = 1/3" result in 0.0?

Question

I am trying to learn interesting behaviour of java. Please explain

    double z  = 1/3;
    System.out.println(z);

This program return 0.0 where as

    double z  = 1/3d;
    System.out.println(z);

This program prints 0.333333. What is the difference.

The first snippet does not print `0.0`, it prints `0`. This question is VERY duplicated. — SJuan76, Sep 29 '14 at 07:00

score 2 · Accepted Answer · answered Sep 29 '14 at 07:00

The first one is an integer division really. It divides an integer by another integer (the result of which is again an integer) and assigns the result to a double variable.

Only the second one yields a double as result.

integer / integer => result is integer, even though assigned to a double variable
integer or double / double => result is double

score 2 · Answer 2 · answered Sep 29 '14 at 07:00

2

first example will divide integers and assign them to your double "z", second divides doubles in the first place

answered Sep 29 '14 at 07:00

riddy

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score 1 · Answer 3 · answered Sep 29 '14 at 07:01

1

Integer/Integer is an Integer even if you assign it to a holder variable of type double.To get a double precision value,you need to do your arithmetic operations using double variables

answered Sep 29 '14 at 07:01

Kumar Abhinav

6,565
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Why does "double z = 1/3" result in 0.0?

3 Answers3