I have the following code for exporting all the items in one of my pods to json. The thing is I don't need all the 130 columns in the json file, but only about 20. Since this will be done for about 150 items I thought I could save some loading time by not printing out all the fields, but I do not know how to do this. For example I only want to print the column value named 'title' for all items in the pod. My code is attached bellow.
<?php
$pods = pods('name', array('orderby' => 'name asc', 'limit' => -1));
$all_companies = $pods->export_data();
if ( !empty( $all_companies ) ) {
die(json_encode($all_companies);
}else{
die(json_encode(array('error' => 'No cars found.')));
}
?>
I thought about doing something like this:
if ( 0 < $all_companies->total() ) {
while ($all_companies->fetch()) {
$json .= $all_companies->field('title');
}
$json = rtrim($json, ",");
$json .= '}}';
}
echo $json;
But it doesn't work and also the code becomes very long.