RequireJS optimization with define functions

Question

I want to build my project to one file. I have three files.

test2.js:

define(
  'test2',
  ['test3.js'],
  function (t2) {
      // test 2
  }
);

test3.js:

define(
  'test3',
  [],
  function () {
      // test 3
  }
);

and main file test1.js:

require(
  ['test2.js'],
  function (t2) {
      // test 1
  }
);

Build config:

({
  baseUrl: '.',
  name: 'test1',
  out: 'built.js',
  optimize: "none"
})

Result:

define(
  'test2',
  ['test3.js'],
  function (t2) {
      // test 2
  }
);

define("test2.js", function(){});

require(
  ['test2.js'],
  function (t2) {
    // test 1
  }
);

define("test1", function(){});

So I dont's see the test3.js code there. Does r.js work only with require dependencies? Can I make it build with define dependencies?

*"When I trying to compile it a get smth about it:"* Huh? Can you clarify that sentence a bit? Are you saying you get an error? (If so, quote it.) Or that you get output like what you follow that sentence with? Or...? — T.J. Crowder, Sep 12 '14 at 09:51
Show your RequireJS runtime configuration and your build configuration too. — Louis, Sep 12 '14 at 09:51

score 0 · Accepted Answer · answered Sep 12 '14 at 09:59

Remove the .js suffix for dependencies, and don't use named modules.

File: test2.js:

define(['test3'],
  function (t2) {
      // test 2
  }
);

File: test3.js:

define([],
  function () {
      // test 3
  }
);

File: test1.js:

require(
  ['test2'],
  function (t2) {
      // test 1
  }
);

RequireJS optimization with define functions

1 Answers1