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I am trying to fetch the number of threads of a process in a UNIX using command line. After going through the man page of unix command, I learnt that following command:

ps -o nlwp <pid>

returns the number of threads spawned in a process.

Whenever i executed above command in unix, it returned:

NLWP
   7

Now, I want to neglect NLWP and a space before 7.

That is I am just interested in a value, as I will be using it in a script, that I am writing for unit testing?

Is it possible to fetch only value, and neglect everything(Title NLWP, space)?

fedorqui
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Ritesh Kumar Gupta
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  • can you reopen your recent question? I understood what you were asking and was working on an answer, even though no one else seems to have. – ysth Nov 12 '14 at 18:10

1 Answers1

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You can always use the --no-headers option in ps to get rid of the headers.

In that case, use awk to just print the first value:

ps --no-headers -o nlwp <pid> | awk '{print $1}'

Or tr to remove the spaces:

ps --no-headers -o nlwp <pid> | tr -d ' '

If --no-headers is not supported in your ps version, either of these make it:

ps -o nlwp <pid> | awk 'END {print $1}'
ps -o nlwp <pid> | tail -1 | tr -d' '
fedorqui
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