sending video stream from server to client using socket programming in python

Question

I am trying to send video stream from server to client using python sockets but facing errors. Here is my server side and client side code.There is some problem with sending frame from server to client ,

Here is my SERVER SIDE code

    #!/usr/bin/env python 



import socket 

import cv2

import json

host = ' ' 

port = 50058

backlog = 5 

size = 1024 

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) 
**strong text**s.bind((host,port)) 
s.listen(backlog) 

vc=cv2.VideoCapture(0)    
if vc.isOpened():

    rval, frame = vc.read()

while 1: 

    client, address = s.accept()
    rval, frame = vc.read()

    #data = client.recv(size) 
    if rval:  
        #print "recieved data " + str(data)
        #print "sending data to %s" % str(address)

        #p=json.dumps(frame)
        client.send(frame) 
    client.close()

And **CLIENT SIDE CODE **


#!/usr/bin/env python 

""" 
A simple echo client 
""" 

import socket
import cv2
import json

host = '169.254.132.51' 
port = 50058
size = 1024000000
cv2.namedWindow("preview")
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) 
s.connect((host,port)) 
while True:

    data = s.recv()
    #frame=json.loads(data)


    cv2.imshow("preview", data)

s.close()

score 4 · Answer 1 · answered Sep 24 '14 at 11:02

You can only send a string or a buffer on a socket. Frame is a numpy array. You have to convert it to string first. Use the following code to convert it to string.

frame = frame.flatten()
data = frame.tostring()

Send data across the network

On the other side use

frame = numpy.fromstring(data, dtype=numpy.uint8)
frame = numpy.reshape(frame, (240,320,3))

to convert it back to a frame that you can pass to cv2.imshow()

I would suggest using UDP instead of TCP as you will have a lower latency.

score 1 · Answer 2 · answered Sep 11 '14 at 09:53

1) The Server closes the connection after 1 send, but the clients seems to expect more than one frame

2) SOCK_STREAM (TCP) only supports a stream without delimiting packets. you need to build the delimiting parts yourself.

3) recvall isn't even a function

maybe you should try implementing it with remote multiprocessing: https://docs.python.org/2/library/multiprocessing.html#using-a-remote-manager

sending video stream from server to client using socket programming in python

2 Answers2