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To clarify my question further:

I have a spring xml file with camel routes. I want to bootstrap this route in a BundleActivator. What are the steps in the OSGI world to initialize and start a SpringContext and register with OSGI registry. I want to do this custom through the api – need to control this rather than use the spring DM. I under stand that I need to use the OSGI classes. Any examples to follow:

This does not start the routes:

ConfigurableApplicationContext  ctx = new GenericApplicationContext();
ConfigurableEnvironment environment = ctx.getEnvironment();
//set up the props for the context
XmlBeanDefinitionReader xmlReader = new XmlBeanDefinitionReader((BeanDefinitionRegistry) ctx);
ClassPathResource classPathResource = new ClassPathResource("context.xml",properClassLoader );
xmlReader.loadBeanDefinitions(classPathResource);
ctx.refresh();
ctx.start();

Thanks.

Chamal Perera
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1 Answers1

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What you are looking for is called Managed Service Factories. Take a look at the description at eclipse gemini project.

Achim Nierbeck
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