How to initialize an unnamed structure element within a named union

Asked Sep 09 '14 at 01:33

Active May 12 '15 at 11:09

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I am using a union and an anonymous structure inside it. I want to know how I can initialize the structure members inside it. how can i do that? Please help :)

typedef union
{
    uint8_t All;                
    struct
    {
        uint8_t G:1;            
        uint8_t O_B:1;         
        uint8_t Unused:1;       
        uint8_t W1:1;          
        uint8_t W2:1;          
        uint8_t Y1:1;          
        uint8_t Y2:1;           
        uint8_t IAQ:1;          
    };
} _UNION_VARIABLE;

_UNION_VARIABLE bit_field_array[5] = { {.G=1, .O_B=0, ...}, {.G=0, .O_B=1, ...},.....};

Is this correct?

asked Sep 09 '14 at 01:33

Ananth

2

did you try to compile it? what does compiler tell you? – Bryan Chen Sep 09 '14 at 01:37
Also, unnamed bitfield values are just that **no name**: `uint8_t : 1;` – David C. Rankin Sep 09 '14 at 05:48
It worked without issues. – Ananth Oct 16 '14 at 18:10

How to initialize an unnamed structure element within a named union

0 Answers0