How do you create a RESTful API with Java servlets?

Question

I am trying to create a simple application using Java and Servlets.

In my app, there are users, and each one should have his/her own page.

I think the URLs for this page should look like:

www.myapp.com/users/john
www.myapp.com/users/paul
...

and so on.

In Django, there are ways to capture parts of the URL. For example, for what I would like to do above, you would create a URL entry like url(r'^articles/([a-z])/$', views.userpage)

How do you do this with Java servlets, web.xml, etc?

Go through a JAX-RS tutorial, Jersey is the Reference Implementation. — Kayaman, Sep 01 '14 at 18:19

Bruno Franco · Answer 1 · 2014-09-01T18:51:43.847

1

@Path("/users/{username}")
public class UserResource {

    @GET
    @Produces("text/xml")
    public String getUser(@PathParam("username") String userName) {
        ...
    }
}

Documentation: http://docs.oracle.com/javaee/6/tutorial/doc/gilik.html

Really nice tutorial: http://www.vogella.com/tutorials/REST/article.html

edited Sep 01 '14 at 18:51

answered Sep 01 '14 at 18:42

Bruno Franco

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Do I need a special library for this to work? – CodyBugstein Sep 01 '14 at 18:58
https://jersey.java.net/download.html – Bruno Franco Sep 01 '14 at 19:12
Is this better than Spring? – CodyBugstein Sep 01 '14 at 19:29
1

It has nothing to do with spring. I should recommend reading some tutorials. – Bruno Franco Sep 01 '14 at 19:57

How do you create a RESTful API with Java servlets?

1 Answers1