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In python-social-auth, when a user registers with an existing email address, an exception is raised.

I managed to catch this exception:

msg =   "%s" % exception

If I print msg, I get the following output:

(1062, "Duplicate entry 'email@id.com' for key 'email_UNIQUE'")

I would like to detect this exception and display a custom error message to the user, something like:

This email id already exists please login with email@id.com or choose to sign in.

So my question is, how do I get only the email address from the exception message? Or is there any shortcut like {{ exception.email }} to get the email address in the template?

Burhan Khalid
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1 Answers1

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use regular expression 

import re

strs="""(1062, "Duplicate entry 'email@id.com' for key 'email_UNIQUE'")"""

email_id =re.findall(r"'(.*?)'", strs, re.DOTALL)[0]
print 'This email id already exists please login with {} or choose to sign in.'.format(email_id)
#output This email id already exists please login with email@id.com or choose to sign in.
sundar nataraj
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