PHP simple test doesn't work

Question

I am developing a page in HTML and PHP, but a specific part of PHP doesn't work (the other parts work, including alerts, database connection, etc)... Does anybody have any clue? Thanks in advance! Gabriel

<form>
    <div class="col-md-4">
        <div class="control-group">
            <label class="control-label" for="edition_eventname">Nome do Evento</label>
            <div class="controls">
                <select id="edition_eventname" name="edition_eventname" class="form-control">   
                    <?php alert("oi"); ?>
                </select>
            </div>
        </div> 
    </div>
    <div class="col-md-4">
    </div>
    <div class="col-md-4">
    </div>
</form>

Your question is very vague. What am I supposed to be looking at and what is your problem? Why are you alerting with php? — Halfpint, Aug 30 '14 at 15:33
PHP doesn't have an `alert()` function. You'll need to implement JS for it. — Funk Forty Niner, Aug 30 '14 at 15:37
Do you want to show a javascript popup or just want to display some text on the page? — PeeHaa, Aug 30 '14 at 15:37
Sorry, it was my mistake. I sometimes mix up the Javascript and PHP functions. New to PHP... — Gabriel Sotero, Aug 30 '14 at 15:37
so what DO you want? only valid code where you have it is php or script that adds options — mplungjan, Aug 30 '14 at 15:40
@PeeHaa more specifically, i was using this to debug, since echoing a text wouldn't work inside a select, would it? — Gabriel Sotero, Aug 30 '14 at 15:41
Sure you can echo out data anywhere you like for debugging purposes. Just look at the source and it will be there. — PeeHaa, Aug 30 '14 at 15:45

TheFrozenOne · Accepted Answer · 2014-08-30T16:00:03.713

1

You can not use alert in PHP. That function does not exist.

There are several other functions that print data.

For example:

<?php
   echo "my String";
   var_dump( $mixedVar );
   print "hello world";
?>

echo and print are not real functions ( language construct ), that's why you can use them with and without parentheses.

edited Aug 30 '14 at 16:00

answered Aug 30 '14 at 15:31

TheFrozenOne

1,695
9
19

Thanks! I always forget this... Not my first time with this problem... Isn't there nothing similar? – Gabriel Sotero Aug 30 '14 at 15:32
http://stackoverflow.com/questions/13837375/how-to-show-an-alert-box-in-php – Gabriel Sotero Aug 30 '14 at 15:33
1

echo "string"; echo $var; – mario Aug 30 '14 at 15:33
1

@mplungjan Nothing similiar to alert(), just print, echo, var_dump. Depends on what OP wants to do. – TheFrozenOne Aug 30 '14 at 15:43
@Doodlebunch var_dump would definitely solve my problem. Thanks for the contribution! – Gabriel Sotero Aug 30 '14 at 15:44
This is not an answer, it's just a fact. The same fact that PHP "answers" you, when you actually look for your error log. Perhaps you want to visit the OP and install yourself into his computers and always read the error log to him? Just curious ^^^ – hakre Aug 30 '14 at 15:48
@hakre It acutally is an answer. – TheFrozenOne Aug 30 '14 at 15:51
Why don't edit and improve it (at least a little bit). It may be an answer (indeed), but it is not useful for anybody right at the moment. – ConcurrentHashMap Aug 30 '14 at 15:53
@ConcurrentHashMap You're right. Is it better now? – TheFrozenOne Aug 30 '14 at 16:00
1

@Doodlebunch Much better! I have reversed my downvote, as it is useful now. Thanks for the edit. – ConcurrentHashMap Aug 30 '14 at 16:06
I also just wanted some extra info. I already know these myself – mplungjan Aug 30 '14 at 18:57
@mplungjan I thought so. But it was so obvious, I thought "it's not a function" was enough. – TheFrozenOne Aug 31 '14 at 10:13

PHP simple test doesn't work

1 Answers1