How I can get an Android phone to vibrate while shaking it?

Question

I am just curious if my app would work out this way to make it vibrate when the phone is shook:

if(event.values[0] > 1.0) {
    vibrator.vibrate(500);
}
else {
    if(event.values[1] > 1.0)
    vibrator.vibrate(500);
}

What I am doing is SensorEventListener and I and combining 2 listeners.

Will this work out doing it this way? I am unable to test it as I don't own an Android phone, so I am asking (programming-wise) if this is possible.

Corneliu Dascălu · Accepted Answer · 2014-08-29T19:07:35.237

1

Yes, it will work that way. Just make sure to stop handling the sensor events for the 500 milliseconds the phone is vibrating.

boolean isVibrating = false;
Handler handler = new Handler(Looper.getMainLooper());

if(!isVibrating){
    if(event.values[0] > 1.0) {
        vibrate(500);
    } else if(event.values[1] > 1.0){
        vibrate(500);
    }
}

void vibrate(long time){
    isVibrating = true;
    vibrator.vibrate(time);
    handler.postDelayed(new Runnable(){
            public void run(){
                isVibrating = false;
            }
        },
        time)
}

edited Aug 29 '14 at 19:07

answered Aug 29 '14 at 18:30

Corneliu Dascălu

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thanks for the answer. for the stop handling part: which method should i use? cancel()? – Rido Aug 29 '14 at 18:53
I don't think you need to stop listening for the sensor. Just toggle a flag and wrap the code in an `if`. – Corneliu Dascălu Aug 29 '14 at 19:02
I've updated the answer with a sample code. I haven't tested it, so it may have syntax errors, but I hope you get the idea. – Corneliu Dascălu Aug 29 '14 at 19:08

How I can get an Android phone to vibrate while shaking it?

1 Answers1