preg_replace from order_address_id to orderAddressID

Question

I am trying to do preg_replace to replace underscore convention to camel case, but the ID needs to have always D uppercase, so e.g. from order_address_id to orderAddressID.

My code looks like below:

$patterns = array(
    '#(' . $pregQuotedSeparator.')([A-Za-z]{1})#',
'#(^[id]{2})|([Id]{2})#',
);

$replacements = array(
    function ($matches) {
        return strtoupper($matches[2]);
    },
    function ($matches) {
        return strtoupper('ID');
    },
);


$filtered = $value;

foreach ($patterns as $index => $pattern) {
    $filtered = preg_replace_callback($pattern, $replacements[$index], $filtered);
}

But I don't know why, it is changing to orderAIDressID?

The linked question is about dashes, I assume you can figure out how to use the same solution for underscores. — Barmar, Aug 29 '14 at 13:08
That seems like a simple step he can do after converting to camelcase, replace `Id` at the end with `ID`. — Barmar, Aug 29 '14 at 13:16
@Bamar , as Ram Sharma said already... this is totally different case as you can see I have done already underscores to camel case. The problem is the D — Marek, Aug 29 '14 at 13:18
@Barmar: This is not a duplicate question, since it need to deal with the particular case of the word "id". Note that this question may be considered as a duplicate more or less only with the approach you suggest that needs to parse the string two times. That is not the case in my answer. — Casimir et Hippolyte, Aug 29 '14 at 13:23

score 0 · Accepted Answer · answered Aug 29 '14 at 13:05

You can use this pattern:

_(id(?![a-z])|[a-z])

The "id" word is tested first, if it is not found only the first letter is captured.

Note that the capture number is 1.

$pattern = '~_(id(?![a-z])|[a-z])~i';
$filtered = preg_replace_callback($pattern,
                                  function ($m) { return strtoupper($m[1]); },
                                  $filtered);

preg_replace from order_address_id to orderAddressID

1 Answers1