How do I create and if condition for strings in python

Question

Hello I've been trying to get this line of code working but it keeps going down to the else: statement. Any ideas?

I cant understand what I'm doing wrong for it not to accept the if: condition.

print('What do you get when you cross a snowman with a vampire?')
answer1 = input()
if answer1.lower 'frostbite':
    print ('Huh? how did you know that YOU SPY!')

else:
    print('FROSBITE!')

Does your code actually read `answer1.lower == 'frostbite'`? — mgilson, Aug 26 '14 at 23:55
@IsmailBadawi -- I doubt that's what OP has. If it is, OP's code _should_ work. — mgilson, Aug 26 '14 at 23:58

score 2 · Accepted Answer · answered Aug 26 '14 at 23:57

It's hard to tell with the code fragment since it has a SyntaxError, but I'm guessing you have:

if answer1.lower == 'frostbite':
    ...

The problem here is that answer.lower is a bound method which is clearly not equal to any string. You need to call it to actually generate the lower case string:

if answer1.lower() == 'frostbite':
    ...

score 0 · Answer 2 · answered Aug 26 '14 at 23:59

0

Someone told me the answer

Thanks friends

print('What do you get when you cross a snowman with a vampire?')
answer1 = input()
if answer1.lower() == 'frostbite':
   print ('Huh? how did you know that YOU SPY!')

else:
    print('FROSBITE!')

answered Aug 26 '14 at 23:59

XxHAMADEHxX

5
1

score 0 · Answer 3 · edited Aug 27 '14 at 00:20

0

You have to compare the strings:

print('What do you get when you cross a snowman with a vampire?')

answer1 = input()

correct = 'frostbite'

if answer1.lower == correct :
    print ('Huh? how did you know that YOU SPY!')

else:
    print('FROSBITE!')

edited Aug 27 '14 at 00:20

Nidal

1,717
1
27
42

answered Aug 27 '14 at 00:00

Benjamin H

46
2

`lower` is actually a method, so you'd want to call it. – Kevin London Aug 27 '14 at 00:48

How do I create and if condition for strings in python

3 Answers3