Javascript location.href for java

Question

There is something like location.href javascript but for java. I need it in a jsp page. I'm using javascript now, but will be better for me in a jsp page. Tx.

Answer 1

If you are using RequestDispatcher.forward() to route the request from controller to the view, you can use in your servlet:

request.getAttribute("javax.servlet.forward.request_uri")

or in JSP:

${requestScope['javax.servlet.forward.request_uri']}

If you want the path of your file from inside the JSP:

${pageContext.request.servletPath}

If you are inside the servlet, you can try this way:

String uri = request.getRequestURI();

String pageName = uri.substring(uri.lastIndexOf("/")+1);

If you are somewhere else:

String port = ( Executions.getCurrent().getServerPort() == 80 ) ? "" : (":" + Executions.getCurrent().getServerPort());
url = Executions.getCurrent().getScheme() + "://" + Executions.getCurrent().getServerName() + port + Executions.getCurrent().getContextPath() +  Executions.getCurrent().getDesktop().getRequestPath();

Answer 2

If you want the browser to navigate to a different location, use a redirect:

http://docs.oracle.com/javaee/5/api/javax/servlet/http/HttpServletResponse.html#sendRedirect(java.lang.String)

If you just want to know which page you are on (its path) then there are is:

request.getRequestURI()  -> /foo/bar?key=value
request.getRequestURL()  -> http://www.domain.de/foo/bar (without query)
request.getPathInfo()    -> /foo/bar (including /)
request.getQueryString() -> key=value (without ?)

But generally have a look here: https://tomcat.apache.org/tomcat-7.0-doc/servletapi/javax/servlet/http/HttpServletRequest.html

Answer 3

Another possible way is to use the RequestDispatcher. Have a look at redirect jsp from servlet RequestDispatcher