How to feed the output of one pipe to another pipe?

Question

I have a command here:

ps aux | grep -i java | grep -i test | awk '{ print $2 }'

which gives only one process id like 1201. Now I want to kill them by piping the 1201 to kill command.

How do I do that?

I tried tee like this:

ps aux | grep -i java | grep -i test | awk '{ print $2 }' | tee >(kill -9)

but that gives:

kill: usage: kill [-s sigspec | -n signum | -sigspec] pid | jobspec ... or kill -l [sigspec]

where I'm making mistake?

possible duplicate of [Killing linux process by piping the id](http://stackoverflow.com/questions/20570999/killing-linux-process-by-piping-the-id) — tripleee, Aug 22 '14 at 11:57
The literal answer to your question is `xargs`, but instead of using this pipe construct you will want to use e.g. `pkill`. — Adrian Frühwirth, Aug 22 '14 at 11:57

score 1 · Accepted Answer · answered Aug 22 '14 at 11:55

1

Use xargs to convert standard input to command-line parameters

ps aux | grep -i java | grep -i test | awk '{ print $2 }' | xargs kill

answered Aug 22 '14 at 11:55

Raul Andres

Also, lose the `grep | grep | awk` -- you can trivially refactor this to a single Awk script. – tripleee Aug 22 '14 at 11:58

1 Answers1