How do you insert variable to url?

Question

I search for a solution, and there are some answers but none solve my problem. I want to add variable to the end of url which is user text input value (this is number of ID to delete in database).

var idRem = parseInt($('#removeId').val(),10);

            $removeBtn.on('click',function(){

                $.ajax({
                      type: 'DELETE',
                      url: "http://rest.learncode.academy/api/kuba/friends/"+idRem,
                      success: function() {
                        //no data...just a success (200) status code
                        console.log('Friend Deleted Successfully!');
                      },
                      error: function() {
                    alert('Deleting error');
                    }
                    });
                });

I see only error message, but when I put manually the value to the url or assign to variable then it works.

Is there anyone knows what is wrong?

What error message you are getting, you probably need to get the removeId value in click handler. — Adil, Aug 22 '14 at 08:58
DELETE http://rest.learncode.academy/api/kuba/friends/NaN 400 (Bad Request), there is Nan instead of number even though I used parseInt — kuba0506, Aug 22 '14 at 09:00
it seems that the problem is in this line: `var idRem = parseInt($('#removeId').val(),10);` idRem is not getting a numerical value - hence - Not a Number (NaN) — Reins, Aug 22 '14 at 09:02
When I type this in console var temp = parseInt($('#removeId').val(),10); I get number not string.typeof temp = "number" — kuba0506, Aug 22 '14 at 09:03

score 0 · Answer 1 · edited Aug 30 '14 at 04:13

0

That's how I do it, and that's working..

$(document).ready(function(){

    $('#btnAddToWatchlist').click(function(){

        location.href="<?php print Yii::app()->createUrl('Products/AddToWatchList'); ?>?id="+<?php print $productid ?>;

    });

});

edited Aug 30 '14 at 04:13

Uyghur Lives Matter

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answered Aug 22 '14 at 08:59

Lucian

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4

Ok, but I prefer JS to PHP this time. – kuba0506 Aug 22 '14 at 09:02
ok then.. just without yii::app()->createUrl.. you only need to add ?id="+ – Lucian Aug 22 '14 at 09:49

score 0 · Answer 2 · answered Aug 22 '14 at 09:15

0

Considering that you are getting a NaN in your idRem variable then i think the problem is WHEN you are calling the initialization. I would try moving the var idRem = parseInt($('#removeId').val(),10); into the function call. Problem might be that the parseInt is called on pageload when there is no value in the #removeId element.

answered Aug 22 '14 at 09:15

Reins

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When I declare 'idRem' with other variables and then idRem = parseInt($('#removeId').val(),10) in a function, there is ReferenceError: idRem is not defined – kuba0506 Aug 22 '14 at 09:27
try declaring + initializing it in the function. – Reins Aug 22 '14 at 16:58

score 0 · Answer 3 · answered Aug 26 '14 at 11:06

The DELETE method requests that the origin server delete the resource identified by the Request-URI.

$.ajax({
url: "http://rest.learncode.academy/api/kuba?" + $.param({"friends": idRem}),
type: 'DELETE',
success: function() {
//no data...just a success (200) status code
console.log('Friend Deleted Successfully!');
},
error: function() {
alert('Deleting error');
}
});

How do you insert variable to url?

3 Answers3