1

I am trying to achieve some thing similar to this question: link

I have this in code: 

#include <stdio.h>
#include <stdlib.h>
struct a *prepareStructA(void);

struct abstract
{
  int x;
  int y;
  int radius;
};

struct a
{
  struct abstract abs;
  //... other data ...
};

//OR Smarter way:
void foo2(struct abstract *data)
{
  int x,y,r;
  x = data->x;
  y = data->y;
  r = data->radius;
}
//Calling foo2 with:
main(){
struct a *sa = prepareStructA();
foo2(sa->abs);
}

but I get this error:

incompatible type for argument 1 of ‘foo2’

expected ‘struct abstract *’ but argument is of type ‘struct abstract’
void foo2(struct abstract *data)

if I change "*data" to "data" i get segmentation error. Can someone please help me out. What I am actually trying to achieve is to pass different structures to same function and perform same operations on them. So any insight on that would be helpful too. Thanks in advance!

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sonalkr132
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  • Besides you probably don't want to pass the structure by-value anyway and you have your answer, I'm a little surprised about the segfault… – mafso Aug 21 '14 at 17:52

1 Answers1

4

You need to pass in the address of the struct:

foo2(&(sa->abs));
jh314
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    yay! it works. Thanks you so much. btw.. I had to change struct a *sa = prepareStructA(); to struct a *sa = (struct a *) malloc(sizeof(struct a)); too. no idea what was prepareStructA() for. – sonalkr132 Aug 21 '14 at 18:04