Finding draw_if_interactive() in pyplot.py

Question

There are multiple draw_if_interactive() expressions in the pyplot module but I can't find this function's definition anywhere in the module.

From intuition and readings, it's an easy guess that the function enables on-demand plotting but where can I read its definition? Thanks.

score 1 · Accepted Answer · answered Aug 19 '14 at 17:56

The function is actually in the backend code. The actual implementation depends on your backend. For example the function with the TkAgg backend is in backend_tkagg.py:

def draw_if_interactive():
    if matplotlib.is_interactive():
        figManager =  Gcf.get_active()
        if figManager is not None:
            figManager.show()

Same kind of functions seem to be for other backends, they use the matplotlib.is_interactive to determine if this is an interactive session and then use the backend specific drawing commands to draw the image.

Thanks very much, this is exactly what I was looking for, a self-contained explanation. :) — user3885774, Aug 19 '14 at 18:32

Finding draw_if_interactive() in pyplot.py

1 Answers1