Run my java app (System Tray) when Windows starts

Question

I have searched on the net, but I have not found anything for my case.

I have created an application, that shows only in the SystemTray (icon) when you start. I want to run the jar file or the exe automatically when windows starts.

I would like to do this via code or automatically directly from my app. A menu item (for example) that the user could click on that option, if desired. I searched the internet but have not found anything. Thank you in advance Thank you very much

Only code Java or Bat

score 2 · Accepted Answer · answered Aug 19 '14 at 17:04

2

I think you can register your application as a system service, set the starttype auto start

answered Aug 19 '14 at 17:04

elevenights

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yes i want to set my app to the windows start, but with the code Java. I read that you can do by transferring the jar file in some folder, possible? @dlbtar – Lorenzo Sogliani Aug 19 '14 at 17:14
@LorenzoSogliani what I do was release. exe file and register as system service. that is to start your application in C program. must have start and stop function for system call – elevenights Aug 19 '14 at 17:36
can you explain an example? ty – Lorenzo Sogliani Aug 19 '14 at 18:06
in VS project, select Files->New->Project->Windows->Windows Service, then write code in OnStart(string[] args) and OnStop() function.The complexity lies in the start JVM in C language.Recommend that you use the [Java Service Wrapper](http://wrapper.tanukisoftware.com/), It's convenient to register java application as system service in common OS. – elevenights Aug 20 '14 at 08:57
in Visual Studio and with language c#? – Lorenzo Sogliani Aug 20 '14 at 09:32
yes. i think Java Service Wrapper may be more convenient, just need to configure parameter. – elevenights Aug 20 '14 at 10:56

score 1 · Answer 2 · answered Aug 19 '14 at 17:14

1

Follow the below steps for windows 7

1)Click the Start windows button , click All Programs, right-click the Startup folder, and then click Open.
2) Open the location that contains the item you want to create a shortcut to.

3) Right-click the item, and then click Create Shortcut. The new shortcut appears in the same location as the original item.

4) Drag the shortcut into the Startup folder.

The next time you start Windows, the program will run automatically.

I got from this link

answered Aug 19 '14 at 17:14

prashant thakre

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Notr that you need use .bat file which having cmmand java -jar and this .bat you need use on startup – prashant thakre Aug 19 '14 at 17:16
Thank you very much, but I'm looking for the instructions (source code) to set my java app (generic) that when windows starts, it is executed well. Only java code @prashant thakre – Lorenzo Sogliani Aug 19 '14 at 17:17
for example for .bat file? – Lorenzo Sogliani Aug 19 '14 at 17:18
just create .bat in your above mentioned startup folder and write inside the .bat as java -jar fullpath/jarname.jar – prashant thakre Aug 19 '14 at 17:22
it's ok but how to create file(bat) and move to correct folder(startup folder) into java code? @prashant thakre – Lorenzo Sogliani Aug 19 '14 at 17:26
`File file = new File("%USERPROFILE%\\AppData\\Roaming\\Microsoft\\Windows\\Start Menu\\Programs\\Startup\\mine.bat"); if(!file.exists()){ file.createNewFile(); }` – prashant thakre Aug 19 '14 at 17:37
Thank you so much and then what do i have to write into the file.bat? @prashant thakre And the path that you have pasted into system windows 8 are wrong, right? – Lorenzo Sogliani Aug 19 '14 at 18:08

Run my java app (System Tray) when Windows starts

2 Answers2