Dynamic Type instantiation C#

Question

I'm looking to instantiate an object at runtime having its type in a string but also it's value in a string. eg:

string myType = "System.Int32";
string myValue = "3";

I'm looking to create an instance of myType and cast/assign myValue into the instance i just created.

I've looked into Activator.CreateInstance :

object objectInstance = Activator.CreateInstance(Type.GetType(myType));

But i can't get to pass my value to my instance (could be anything : int16/32/64, double, bool, custom type...).

Thank you for your help

How do you know which property to set in case of custom types? — Marcel N., Aug 12 '14 at 13:07

score 1 · Answer 1 · answered Aug 12 '14 at 13:14

1

That only works on value types...

var t = Type.GetType("System.Int32");
object x = Activator.CreateInstance(t);

if (t.IsValueType)
   x = Convert.ChangeType("2", t);

answered Aug 12 '14 at 13:14

gsharp

Thank you ! Works perfectly fine :) Is there any way to specify a custom type is a Value type ? – Caracole Aug 12 '14 at 13:37
I dont understand what you mean @Caracole. – gsharp Aug 12 '14 at 15:15

score 0 · Accepted Answer · answered Aug 12 '14 at 13:19

0

You need to get the type object and then use the Convert class:

string myType = "System.Int32";
Type type=Type.GetType(myType)

string myValue = "3";
object convertedValue = Convert.ChangeType(myValue, type);

answered Aug 12 '14 at 13:19

Sean

2 Answers2