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What will [[UIDevice currentDevice] model] return for "iPad"?

Arun_
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g.revolution
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    This is under NDA, so your question is likely to be ignored until the NDA is lifted. The documentation states that `model` returns a string like "iPod Touch" or "iPhone" for those respective devices, so one cane make an educated guess.. – Jasarien Mar 26 '10 at 10:32
  • @Jasarien: If I am not wrong the sdk version beta_5 is not under NDA, Please correct me if I am wrong. – Madhup Singh Yadav Mar 29 '10 at 06:25
  • @Madhup, I believe it still is. At the iPhone Developer site, the warning is still in place that says: "iPhone SDK 3.2 beta 5 is pre-release software and is considered Apple Confidential Information." While it can be used to submit iPad apps, it is still under NDA. – Jasarien Mar 29 '10 at 08:31

4 Answers4

3

I tried using containsString but it was not allowed with xcode4

Here is how I solved it:

if ([[[UIDevice currentDevice] model] hasPrefix:@"iPhone"])
    {

Hope this helps even if its a bit late.

timv
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2

You can use UI_USER_INTERFACE_IDIOM(), which will either return UIUserInterfaceIdiomPhone or UIUserInterfaceIdiomPad. Bear in mind that on any device < 3.2, this is unavailable, so first check to see whether the property can be retrieved - in this case, it is not an iPad.

Or, alternatively, to specifically work out whether the platform is an iPad or not, use 

if ([[[UIDevice currentDevice] model] containsString:@"iPad"]) {
    // Your code goes here
}

Hope this helps ;)

jrtc27
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1

Well trying on simulator:

NSLog(@"%@",[[UIDevice currentDevice] model]);

it gives iPad Simulator, will update the answer when I will get the device ;)

Madhup Singh Yadav
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0

You might try the Apple Developer Forums.

Alex Reynolds
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