Why won't this println command start a new line?

Question

Here's the relevant code:

public static void printBoarders (Territory x) 
{
    int t = 0 ; 
    int n = 0 ; 
    for (int i = 0; i<x.borders.length; i++)
    {
        if (x.borders[i] == -1) 
            t = i ; 
    }
    for (int j = 0; j<x.borders.length; j++) 
    {
        if (x.borders[j] == 1) 
            n++ ;
    }

    Territory.translate (t) ;
    System.out.print (" has " + n + " borders: ") ;
    Territory.translate (x.borders) ;
    System.out.println (" ") ; 
}

When I run this, I get everything on one line without a line break. Why isn't the System.out.println (" ") ; creating a line break?

Here is an example of what the output winds up being:

Northwest Territory, Alberta, Kamchatka, hidavid-names-macbook-pro:~ davidname$

EDIT: the problem was that this method was never being invoked. A different one which i was replacing was. All is well.

It looks to me like that output doesn't come from the code you're showing here. Where is the "has" and the "borders:"? — Carl Norum, Mar 24 '10 at 17:55

score 2 · Answer 1 · answered Mar 24 '10 at 17:58

2

None of the code you're showing is what's outputting "Northwest Territory, Alberta, Kamchatka".

What does .translate() do? It's got to be in there.

answered Mar 24 '10 at 17:58

Dean J

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score 1 · Answer 2 · answered Mar 24 '10 at 17:54

1

i dont see it printing has " + n + " borders: either, so im going to say the code is never executed for some reason

answered Mar 24 '10 at 17:54

mkoryak

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score 1 · Answer 3 · answered Mar 24 '10 at 17:54

1

I can see only

System.out.print (" has " + n + " borders: ") ;

Actually I don't understand why you see any other output then

" has 5 borders: "

answered Mar 24 '10 at 17:54

Roman

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what do you mean thats all you see? – David Mar 24 '10 at 17:56
1

@David: that means that you posted wrong peace of code (or it's better to say you posted only part of the code) – Roman Mar 24 '10 at 17:57

score 1 · Accepted Answer · answered Mar 24 '10 at 18:02

1

The code snippit above would start a new line. The problem is that the method printBoarders isn't being invoked.

answered Mar 24 '10 at 18:02

David

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score 0 · Answer 5 · edited Mar 24 '10 at 17:58

0

I believe it's starting from the middle of the line where the last System.out.print call left it.

from the docs for PrintWriter, e.g.

public void println(String x)

Prints a String and then terminates the line.

edited Mar 24 '10 at 17:58

Roman

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answered Mar 24 '10 at 17:54

Steve B.

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score 0 · Answer 6 · answered Mar 24 '10 at 17:54

0

Only the last print is println, the first is just print so only the space " " is printed to a new line at the end...

EDIT: You mean when you call it multiple times?Y

answered Mar 24 '10 at 17:54

Tamar

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if it were printed on a new line then davvid-names-backboo-pro:~davidname$ would be printed below it. – David Mar 24 '10 at 17:56

score 0 · Answer 7 · answered Mar 24 '10 at 17:55

0

Just quickly scanning this code, it look like the println() does seem to be reached. Actually the I'm not even seeing how you got the output you did. Is this the complete code. This is a great case for writing a small unit test.

answered Mar 24 '10 at 17:55

Vinny

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why does it seem like its not reached? – David Mar 24 '10 at 17:58

Why won't this println command start a new line?

7 Answers7