Formatting numbers in Java / Indian numbering system

Question

I want to obtain number in following format:

1000   =    1,000
10000  =   10,000
100000 = 1,00,000

I tried this:

import java.text.DecimalFormat;

public class StringProcessingDemo {

public static void main(String[] args) {
     String pattern = "##,##,###.###";
        DecimalFormat myFormatter = new DecimalFormat(pattern);
        String output = myFormatter.format(2564484.125);            
        System.out.println(output);
    }
}

But despite of pattern ##,##,###.### I am getting output as 2,564,484.125 while I think I should get it as 25,64,484.125. Why?

@Tichodroma `25,64,484.125` is having comma separator at [lakh](http://en.wikipedia.org/wiki/Lakh)'s place instead of million's place along with thousands place — Mahesha999, Aug 01 '14 at 10:40
But I dont see why that pattern does not produce what I want — Mahesha999, Aug 01 '14 at 10:42

score 4 · Answer 1 · answered Aug 01 '14 at 11:13

4

You can achieve your requirement with this

public static String format(double value) {
    if(value < 1000) {
        return format("###", value);
    } else {
        double hundreds = value % 1000;
        int other = (int) (value / 1000);
        return format(",##", other) + ',' + format("000", hundreds);
    }
}

private static String format(String pattern, Object value) {
    return new DecimalFormat(pattern).format(value);
}

answered Aug 01 '14 at 11:13

SparkOn

8,806
4
29
34

yess but it trims the fractional part – Mahesha999 Aug 01 '14 at 11:26
`format(2564484.125)` prints `25,64,484` – Mahesha999 Aug 01 '14 at 11:29
nyways got the answer [here](http://stackoverflow.com/a/14510951/1317018) – Mahesha999 Aug 01 '14 at 11:30

score 2 · Answer 2 · edited Jun 20 '20 at 09:12

2

But despite of pattern ##,##,###.### I am getting output as 2,564,484.125 while I think I should get it as 25,64,484.125. Why?

You can supply multiple grouping characters, but only one is used. From the Javadoc:

If you supply a pattern with multiple grouping characters, the interval between the last one and the end of the integer is the one that is used.

So "#,##,###,####" == "######,####" == "##,####,####"

It seems that formatting the Lakh format is not possible with standard Java mechanisms, see Number formatting in java to use Lakh format instead of million format for a solution.

edited Jun 20 '20 at 09:12

Community

1
1

answered Aug 01 '14 at 10:42

Andreas Fester

36,091
7
95
123

ohh surprising that, but then unintutive, how I can achieve what I want then? – Mahesha999 Aug 01 '14 at 10:44

score -1 · Answer 3 · edited Feb 27 '19 at 16:23

This may be because of number format: million, billion, and trillion...... So, I have created a java function for your need:

String lakhFormattedComma(Double d) {
  String[] str = d.toString().split("\\.");
  int len = str[1].length();
  if (str[1].substring(len - 3, len - 1).equals("E-")) {
    return String.format("%." + (len - 3 + Integer.valueOf(str[1].substring(len - 1))) + "f", d);
  } else if (str[1].substring(len - 2, len - 1).equals("E")) {
    str = String.format("%." + (len - 2 - Integer.valueOf(str[1].substring(len - 1))) + "f", d).split("\\.");
  }
  String out = "." + str[1];
  len = str[0].length();
  if (len < 3) {
    return str[0] + out;
  }
  out = str[0].substring(len - 3) + out;
  for (int i = len - 5; i >= 0; i = i - 2) {
    out = str[0].substring(i, i + 2) + "," + out;
    if (i == 1) {
      out = str[0].substring(0, 1) + "," + out;
    }
  }
  return out;
}

Formatting numbers in Java / Indian numbering system

3 Answers3