Picture display with PHP

Question

I've a problem with some lines of code. I try to generate a picture with php and the gd2 librarie.

<?php

header('Content-type: image/jpeg');

$im = imagecreatefromjpeg('profil.jpg');
imagejpeg($im);

imagedestroy($im);?>

This code doesn't work. There's no image displayed, just a message : "this image can't be displayed because there's error" displayed in white on grey background.

The picture is well loaded and "$im" is a resource created with "imagecreatefromjpeg"...

If i remove all lines except header('Content-type: image/jpeg');, I've got the same problem.

Who can give me the right way ??

Thanks by advance !

Mickael

Can you please post a screenshot of the error message in the browser? I don't really get where the error is coming from. (Browser, PHP, GD, Apache, etc.) — Rudolph Gottesheim, Jul 30 '14 at 21:26
maybe your image is not a real JPEG image, but a PNG or GIF one. Please do var_dump($im); before `imagejpeg($im)` this may help to debug — Valentin Mercier, Jul 30 '14 at 21:28
I've already do a var_dump of $img before "imagejpeg", It's return "Resource(3)", so "imagecreatefromjpeg" don't return FALSE. — moDevsome, Jul 31 '14 at 06:18

score 0 · Answer 1 · answered Jul 30 '14 at 22:10

0

Nmae that php file image.php and call it as source of image tag in another php file. Then that will show the image.

 <img src="image.php" height="250px" width="162px">

Click Here To Download Example From Google

answered Jul 30 '14 at 22:10

Muhammad Ashikuzzaman

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Thankz for your idea, but It's don't work, there's no picture displayed, like if the picture is not found on a location – moDevsome Jul 31 '14 at 06:19
It is working in my computer.Please then clear your cookie and saved files in your browser. – Muhammad Ashikuzzaman Jul 31 '14 at 11:09
Did you download the example? Please download it and run it. @MOWebCreation – Muhammad Ashikuzzaman Jul 31 '14 at 11:10

score 0 · Accepted Answer · answered Oct 21 '14 at 19:51

0

Working good after creating a new php file where I pasted my code.

I think that my file was corrupt.

answered Oct 21 '14 at 19:51

moDevsome

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score -1 · Answer 3 · answered Jul 30 '14 at 21:26

-1

I just tried your code. The only error I get is when profil.jpg is not present in the same directory. is profil.jpg in the same directory as your .php file ?

answered Jul 30 '14 at 21:26

Sylvain Cyr

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That's what I wanted to ask, but he wrote "'$im' is a resource". So I'm guessing the loading of the file worked just fine. Also, this is not an answer. :P – Rudolph Gottesheim Jul 30 '14 at 21:28
this is a comment, not an answer – Jul 30 '14 at 21:29
this is not a comment, it was a possibility that the problem was only that. – Sylvain Cyr Jul 30 '14 at 21:33
The picture is in the same folder and well loaded – moDevsome Jul 31 '14 at 06:21

Picture display with PHP

3 Answers3