PHP strtotime date difference

Question

I want to get the age of users. I tried:

$dStart = strtotime('1985-10-24');
    $dEnd   = strtotime('2014-07-30');
    $dDiff  = $dEnd - $dStart;
    echo date('Y',$dDiff);

But get 1998 instead 28, what would be the right code?

Think about what you're actually calculating with *timestamp - timestamp*. The result would be the number of seconds between the two dates which is itself, not a date — Phil, Jul 29 '14 at 23:37
I got this code from a question here and it was marked as accepted. I knew that couldn't be right but I can't think of something else — user3838972, Jul 29 '14 at 23:40
I got it from here: http://stackoverflow.com/questions/15743882/php-date-difference ok that wasn't accepted but voted up — user3838972, Jul 29 '14 at 23:44

score 4 · Accepted Answer · answered Jul 29 '14 at 23:38

4

strtotime() is not made for date math. DateTime() is much better suited for this:

$dStart = new DateTime('1985-10-24');
$dEnd = new DateTime('2014-07-30');
$dDiff = $dStart->diff($dEnd);
echo $dDiff->y;

answered Jul 29 '14 at 23:38

John Conde

$d1 and $d2 != $dEnd and $dStart – AbraCadaver Jul 29 '14 at 23:40
Somehow my original text was in my clipboard instead of my eval.in code. Thanks for pointing that out as I didn;t notice it when I pasted it here. – John Conde Jul 29 '14 at 23:41

1 Answers1