array_unique not sorting values from regular expression

Question

So I have the following regex and I count the occurrences of matches like so:

preg_match_all("/".$toArray."/i", $input, $matches);

$count_matches = count($matches[0]);

However, I want to get only those matches that are unique. And applying array_unique() to the following does not seem to work.

$count_matches = count(array_unique($matches[0]));

Does the key [0] mess it up? If so how can I go round this?

Can I do something like this? `$count_matches = count($matches[0]);` `$unique = $count_matches - array_unique(count($matches));` — Julian Sanders, Jul 20 '14 at 23:25

score 0 · Answer 1 · answered Jul 20 '14 at 23:12

0

It seems you are trying to count an array location

$count_matches = count($matches[0]);

This tries to count position 0 in the array $matches. Instead of counting how many positions are in the entire array $matches.

answered Jul 20 '14 at 23:12

jjonesdesign

How can I keep the count and in the same get only the unique values? – Julian Sanders Jul 20 '14 at 23:17

1 Answers1