Unix open file from line X or first 100 lines after Z found

Question

I have a 2GB text file and I want to read every line 100 lines after a certain string is found example:

string: 'epicvar (string) ="5"'

string was found on line 5000 so I want to read the file from 5000 to 5100 then the string was also found on line 15000 so I want to read the file from 15000 to 15100 and so on.

The system used is HP-UX B.11.31 U

Could you update tags indicating your OS? It looks like you are on Solaris or AIX — fedorqui, Jul 17 '14 at 09:17
I would suggest compiling and installing [GNU grep](http://www.gnu.org/software/grep/) (perhaps with `./configure --prefix=$HOME/soft/` if you don't have root access) theu using the `grep -A100` as suggested in the deleted [answer by Fedorqui](http://stackoverflow.com/a/24799223/841108) — Basile Starynkevitch, Jul 17 '14 at 09:31
company server :D can't do those installs as I please ...unfortunatly — Edmund Simpson, Jul 17 '14 at 10:02

score 2 · Accepted Answer · answered Jul 17 '14 at 10:33

2

This may work for you (untested), if you understand ll2p means last line to printit should be easy enough to read...

awk '/pattern/ {ll2p = NR+100}
        NR < ll2p {print}
        NR==ll2p {ll2p=0} ' file

answered Jul 17 '14 at 10:33

Mark Setchell

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I tryed but it didn't output a thing ... maybe as something to do whit the "" in the pattern ??? awk '/epicvar (string) ="5"/ {ll2p = NR+100} NR < ll2p {print} NR==ll2p {ll2p=0} ' myfolder/myfile – Edmund Simpson Jul 17 '14 at 13:22
Try just using `awk '/epicvar.*string.*5/...` – Mark Setchell Jul 17 '14 at 13:55

Unix open file from line X or first 100 lines after Z found

1 Answers1