regular expression to remove string following

Question

http://www.example.com/product/9896341.html?utm_source=google&utm_medium=VRM&utm_campaign=N&cid=vizuryjz&utm_content=&color=red&pid=9896341

in the above url, i need to remove text followed in utm_source=google, suppose if in url utm_source="text" i need to replace "utm_source=text" with "".

please guys help me for regular expression.

This is more a feature request than a question about resolving some broken code. Just use online tools like http://www.regexr.com/ and learn to do your own. — GillesC, Jul 11 '14 at 09:37

score 0 · Accepted Answer · answered Jul 11 '14 at 09:44

0

Instead of gawk, I would recommend using gnu sed for this:

$ s="http://www.example.com/product/9896341.html?utm_source=google&utm_medium=VRM&utm_campaign=N&cid=vizuryjz&utm_content=&color=red&pid=9896341"
$ sed -r 's/utm_source=[^&]+//' <<<"$s"
http://www.shopin.net/product/9896341.html?&utm_medium=VRM&utm_campaign=N&cid=vizuryjz&utm_content=&color=red&pid=9896341

This deletes utm_source= followed by anything up to the next ampersand.

answered Jul 11 '14 at 09:44

Tom Fenech

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i did like this (utm_?([^\&]+)?&) can u check please – chethi Jul 11 '14 at 10:08

score 0 · Answer 2 · answered Jul 11 '14 at 09:45

0

you can use this regex

    utm_source=[^&?=]*

javascript

    your_url.replace(/utm_source=[^&?=]*/gi,"")

sed

    echo "http://www.shopin.net/product/9896341.html?utm_source=google&utm_medium=VRM&utm_campaign=N&cid=vizuryjz&utm_content=&color=red&pid=9896341" | sed s/utm_source\=\[\^\&\?\=\]\*//g

answered Jul 11 '14 at 09:45

alexanderlz

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i did like this (utm_?([^\&]+)?&), can u check please – chethi Jul 11 '14 at 10:08
What are you trying to achieve? – alexanderlz Jul 11 '14 at 10:15

regular expression to remove string following

2 Answers2