Tweets in Python

Question

def twitter_search(twitter_api,q,max_results=200,**kw):    
    search_results = twitter_api.search.tweets(q=q,count=100,**kw)
    statuses = search_results['statuses']
    max_results=min(1000,max_results)
    for _ in range(10):
        try:
            next_results = search_results['search_metadata']['next_results']
        except KeyError, e:
            break
        kwargs = dict([ kv.split('=')
                for kv in next_results[1:].split("&") ])
        search_results = twitter_api.search.tweets(**kwargs)    
        statuses += search_results['statuses']
        if len(statuses) > max_results:
            break
        return statuses


results = twitter_search(twitter_api,q,max_results=10)
print json.dumps(results[0], indent =1)

The last line is returning an error that 'NoneType' object has no attribute __getitem__

Looks like `results is None`. What have you done to find out why? — jonrsharpe, Jul 10 '14 at 13:19
I have tried reading more about the error. some are saying that results can't be indexed. I'm confused. — Kushal Agarwal, Jul 10 '14 at 13:21
So you didn't, for example, `print results` to find out what it is? — jonrsharpe, Jul 10 '14 at 13:23
Hint: if you `break` out of the `for` cycle, what will be returned? — Stefano Sanfilippo, Jul 10 '14 at 13:26
@KushalAgarwal OK, so your function is returning `None` - why didn't you say that, and what did you do to try to figure out why that is happening? — jonrsharpe, Jul 10 '14 at 13:31

score 0 · Accepted Answer · answered Jul 10 '14 at 15:20

You have two issues here:

The return statement is inside the for loop, and might not be reached if the loop hits one of the break statements first. If it is reached, it will return earlier than you want, without running the rest of the loop iterations.
You are assuming results will have at least one element (results[0]). If results is an empty list, this will fail with an IndexError.

Solution:

Move the return statement outside of the for loop (dedent one level).
Check if results: before indexing into it.

score 0 · Answer 2 · answered Aug 06 '16 at 17:07

The problem is q not have trends :S

q =  '#vladimirala1'  


count = 100

search_results = twitter_api.search.tweets(q=q, count =count)

statuses = search_results['statuses']


for _ in range(5):
  print "Length of statuses", len(statuses)
  try:
    next_results = search_results['search_metadata']['next_results']
  except KeyError, e: # No mas resultados si no hay mas datos
    break
  
  kwargs = dict([kv.split('=') for kv in next_results[1:].split('&') ])
  
  search_results = twitter_api.search.tweets(**kwargs)
  
  statuses += search_results['statuses']
  

print json.dumps(statuses[0], indent=1)

Tweets in Python

2 Answers2