How capture image from ip camera with PHP

Question

So far i have this code which never stop loading

camera.php

$img = 'http://userid:password@ipaddress/mjpgstreamreq/1/image.jpg'; 
header ('content-type: image/jpeg'); 
readfile( $img );

index.html

<img src="camera.php" />
<!-- But this does not work -->

and if I have in a img tag on the page with this url as the src also never stop loading the page, and I am trying to read just the snapshot it is not a continues frames this is a recorded picture took with the ip camera, that I want to read and save in a file for future needs, and I am at localhost and the ip camera is in another network if it matters, so how can I read this without this continues loading.

The whole idea behind this is that I am trying to do a way to avoid the popup asking for login information, so everybody can see the latest picture of construction site and they know that the cameras are working there, I just want to display the image on a website — Lucas M. Oliveira, Jul 09 '14 at 03:06
I try to use one php proxy from a guy on github no success at all — Lucas M. Oliveira, Jul 09 '14 at 03:10
[link](https://github.com/zyphlar/ip-camera-proxy/blob/master/snapshot.php) and this is link for proxy on github — Lucas M. Oliveira, Jul 09 '14 at 03:10

score 2 · Accepted Answer · answered Sep 23 '14 at 21:50

Try this out, but remember to change the username, password, ip and port on your Ip cam

<img src="http://myServer.com/cam.php" width="640" height="380" name="refresh">

<script language="JavaScript" type="text/javascript">     
  image = "http://myServer.com/cam.php"
  function Start() {
   tmp = new Date();
   tmp = "?"+tmp.getTime()
   document.images["refresh"].src = image+tmp
   setTimeout("Start()", 1000)
  }
    Start();       
</script>

<?php
 error_reporting(E_ALL);
 $img="IPCAM_IP:PORT/snapshot.cgi?user=UserName&pwd=Password"; 
 header ('content-type: image/jpeg');
 readfile($img); 
?>

score 0 · Answer 2 · answered Jul 09 '14 at 04:00

0

The resource you are requesting using readfile() is a motion JPEG stream, not just a single image. As such, the readfile() operation will never end — it will just keep on spitting out more images as the stream continues!

You will need to implement code to open the resource as an HTTP stream, parse out a single JPEG from the stream, and stop reading. This may not be simple.

answered Jul 09 '14 at 04:00

do you have any idea how i might set up a loop to just a get jpg from this mjpg – Lucas M. Oliveira Jul 10 '14 at 04:40

How capture image from ip camera with PHP

2 Answers2