Parsing xml with simplexml_load

Question

I am trying to parse an xml but I get a problem while I am trying to fetch image url.

My xml is:

<entry>
<title>The Title</title>
<id>http://example.com/post/367327.html</id>
<summary>Some extra text</summary>
<link rel="enclosure" href="http://example.com/photos/f_0px_30px/image687.jpg" type="image/jpeg"  length="" /> 
</entry>

So far I am using the code below to fetch the other data:

$url = "http://msdssite.com/feeds/xml/myxml.xml";
$xml = simplexml_load_file($url);

foreach($xml->entry as $PRODUCT)
{
$my_title = trim($PRODUCT->title);
$url = trim($PRODUCT->id);
$myimg = $PRODUCT->link;
}

How can I parse the href from this: <link rel="enclosure" href="http://example.com/photos/f_0px_30px/image687.jpg" type="image/jpeg" length="" />

Try `$myimg = (string) $PRODUCT->link->attributes()->href;` – HamZa Jul 07 '14 at 01:10 — HamZa, Jul 07 '14 at 01:10

Casimir et Hippolyte · Accepted Answer · 2014-07-07T03:19:31.900

Since it seems that your entries can contain several link tags, you need to check that the type attribute has the value image/jpeg to be sure to obtain a link to an image:

ini_set("display_errors", "On");

$feedURL = 'http://OLDpost.gr/feeds/xml/category-takhs-xatzhs.xml';

$feed = simplexml_load_file($feedURL);

$results = array();

foreach($feed->entry as $entry) {
    $result = array('title' => (string)$entry->title,
                    'url'   => (string)$entry->id);

    $links = $entry->link;
    foreach ($links as $link) {
        $linkAttr = $link->attributes();
        if (isset($linkAttr['type']) && $linkAttr['type']=='image/jpeg') {
            $result['img'] = (string)$linkAttr['href'];
            break;
        }
    }
    $results[] = $result;
}

print_r($results);

Note that using simplexml like that (the foreach loop to find the good link tag) isn't very handy. It's better to use an XPath query:

foreach($feed->entry as $entry) {
   $entry->registerXPathNamespace('e', 'http://www.w3.org/2005/Atom');
   $results[] = array(
     'title' => (string)$entry->title,
     'url'   => (string)$entry->id,
     'img'   => (string)$entry->xpath('e:link[@type="image/jpeg"]/@href')[0][0]
   );
}

Yes but how can echo the results as single? For example how can i echo only each image url? — Irene T., Jul 07 '14 at 12:51
@IreneT.: I have made the choice to put all in a result array to be more clean and because its more handy to reuse the results later, example: `echo $results[2]['img'];` displays the image url from the third entry. But if you don't need a result array at all and you only want to display the image url, replace `$results[].....);` with `echo (string)$entry->xpath('e:link[@type="image/jpeg"]/@href')[0][0];` — Casimir et Hippolyte, Jul 07 '14 at 13:03

score 1 · Answer 2 · answered Jul 07 '14 at 01:46

If that's the exact XML, actually there is no need for a foreach. Try this:

$xml = simplexml_load_file($url);

$my_title = (string) $xml->title;
$myimg = (string) $xml->link->attributes()['href']; // 5.4 or above
echo $myimg; // http://example.com/photos/f_0px_30px/image687.jpg

score 0 · Answer 3 · answered Jul 07 '14 at 01:26

0

Try:

foreach($xml->entry as $PRODUCT)
{
$my_title = trim($PRODUCT->title[0]);
$url = trim($PRODUCT->id[0]);
$myimg = $PRODUCT->link[0];
}

answered Jul 07 '14 at 01:26

Phongdatgl

58
7

Parsing xml with simplexml_load

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