NSString with \n or line break

Question

Does anyone know how to use line breaks in NSString? I need to do something like this -

[NSString stringWithFormat:@"%@,\n%@", mystring1,mystring2];

Did you actually try this? Because if you had, you would've gotten your answer. — Dave DeLong, Mar 17 '10 at 01:09
no it didn't work. i see the \n appended to the string but when it renders, it is on the same line. — Dave, Mar 17 '10 at 16:20
Please make sure this NSString type message you are displaying not using HTML support. If using HTML support, it will not treat \n . Hope i am helpful. Thanks, Aby — Abdul Yasin, May 21 '14 at 09:47

Anthony F · Answer 1 · 2012-06-13T22:42:31.637

180

I just ran into the same issue when overloading -description for a subclass of NSObject. In this situation I was able to use carriage return (\r) instead of newline (\n) to create a line break.

[NSString stringWithFormat:@"%@\r%@", mystring1,mystring2];

edited Jun 13 '12 at 22:42

answered Apr 08 '11 at 19:07

Anthony F

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perfect! Just note that you have an un-needed comma after the first %@ – Sam Spencer Apr 21 '12 at 19:22
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@OMGPOP, note that for iOS development you also need to check out my answer below. – Andy A Aug 07 '13 at 08:41

score 32 · Answer 2 · answered Apr 28 '11 at 13:07

32

If your string is going in a UIView (e.g a UILabel), you also need to set the number of lines to 0

myView.numberOfLines=0;

answered Apr 28 '11 at 13:07

Andy A

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score 26 · Answer 3 · answered Aug 14 '14 at 13:22

I found that when I was reading strings in from a .plist file, occurrences of "\n" were parsed as "\\n". The solution for me was to replace occurrences of "\\n" with "\n". For example, given an instance of NSString named myString read in from my .plist file, I had to call...

myString = [myString stringByReplacingOccurrencesOfString:@"\\n" withString:@"\n"];

... before assigning it to my UILabel instance...

myLabel.text = myString;

score 12 · Answer 4 · edited May 08 '15 at 17:56

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NSString *str1 = @"Share Role Play Photo via Facebook, or Twitter for free coins per photo.";
NSString *str2 = @"Like Role Play on facebook for 50 free coins.";
NSString *str3 = @"Check out 'What's Hot' on other ways to receive free coins";


NSString *msg = [NSString stringWithFormat:@"%@\n%@\n%@", str1, str2, str3];

edited May 08 '15 at 17:56

Alex Zavatone

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answered Jan 10 '14 at 10:50

Mohit

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score 8 · Answer 5 · edited Jan 13 '22 at 01:54

8

try this

 [NSString stringWithFormat:@"%@\n%@",string1,string2];

edited Jan 13 '22 at 01:54

mfaani

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answered Feb 22 '14 at 11:29

score 2 · Answer 6 · answered Oct 03 '13 at 07:21

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\n\r seems working for me.

I am using Xcode 4.6 with IOS 6.0 as target. Tested on iPhone 4S. Try it by yourself.

Feng Chiu

answered Oct 03 '13 at 07:21

us_david

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this is not an answer..please write these in comments. – Kundan Oct 03 '13 at 07:38

score 2 · Answer 7 · edited Sep 15 '22 at 10:37

2

Line breaks character for NSString is \r

correct way to use [NSString stringWithFormat:@"%@\r%@",string1,string2];

\r ----> carriage return

edited Sep 15 '22 at 10:37

Shebuka

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answered Nov 25 '14 at 07:00

Chamath Jeevan

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"StringWithFormat" is invalid; it should be "stringWithFormat" (must start with lower case 's') – SpokaneDude Nov 12 '16 at 18:41

score 1 · Answer 8 · edited Oct 14 '16 at 07:57

1

\n is the preferred way to break a line. \r will work too. \n\r or \r\n are overkill and may cause you issues later. Cocoa, has specific paragraph and line break characters for specific uses NSParagraphSeparatorCharacter, NSLineSeparatorCharacter. Here is my source for all the above.

edited Oct 14 '16 at 07:57

Jagat Dave

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answered Aug 16 '16 at 08:19

mahboudz

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score 1 · Answer 9 · answered Apr 04 '18 at 06:09

In case \n or \r is not working and if you are working with uiwebview and trying to load html using < br > tag to insert new line. Don't just use < br > tag in NSString stringWithFormat.

Instead use the same by appending. i.e by using stringByAppendingString

 yourNSString = [yourNSString stringByAppendingString:@"<br>"];

score 0 · Answer 10 · answered Mar 17 '17 at 23:06

0

In Swift 3, its much simpler

let stringA = "Terms and Conditions"
let stringB = "Please read the instructions"

yourlabel.text =  "\(stringA)\n\(stringB)"

or if you are using a textView

yourtextView.text =  "\(stringA)\n\(stringB)"

answered Mar 17 '17 at 23:06

Naishta

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Post is specifically labeled for Objective-C. – Dylan Dec 20 '18 at 04:33

NSString with \n or line break

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